CHEMISTRY HELP!!!!!!?
ans: (c) remain same
when concentration of 1 of reactants doubled, equilibrium adjust compensate change (le-chatelier's principle).
consider following hypothetical reaction:
+ b -> c + d
equilibrium constant constant given system @ equilibrium, under given conditions of temperature etc. varying concentrations of reactants not affect equilibrium constant; rather, final equilibrium concentrations of reactants decided equilibrium constant. change in final concentrations ratio k = ([c][d])/([a][b]) remains constant.
hope helped!
in reversible chemical reaction @ equilibrium, if concentration of 1 of reactants doubled, equilibrium constant
(a) doubled
(b) halved
(c) remain same
(d) become one-fourth
pls explain answer in detail....thx :)
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