Chemistry? 10 points to the first correct answer?
write balanced equation, use stoichiometry calculate number of moles of product. use molar mass calculate mass of product 15.0g of starting material.
2 ch3cooag + cuso4 ==> ag2so4 + cu(ch3coo)2
15.0mg = .015g
ch3cooag = 166.91g / mol
cuso4 = 159.61g / mol
agso4 = 311.80g / mol
cu(ch3coo)2 = 181.63g / mol
divide 0.015g molar mass of reactants.
agch3coo = 0.015g x 1mol / 166.91g = 8.99 x 10^5mol
cuso4 = 0.015g x 1mol / 159.61g = 9.40 x 10^5mol
use chemical equation find number of moles of product. silver acetate limiting reactant.
8.99 x 10^-5 ch3cooag + 9.40 x 10^-5 cuso4 = ag2so4 + cu(ch3coo)2
**made mistake here, fixed**
silver acetate limiting reactant use 4.5 x 10^-5mol of agso4 because of 2:1 ratio of ag. ch3coo has 2:2 ratio don't change it.
8.99 x 10^-5 ch3cooag + 8.99 x 10^-5 cuso4 = 4.5 x 10^-5 ag2so4 + 8.99 x 10^-5 cu(ch3coo)2
multiply number of moles of product molar masses
4.50 x 10^-5mol ag2so4 x 311.80g / mol = 0.014g ==> 14mg
8.99 x 10^-5mol cu(ch3coo)2 x 181.63g / mol = 0.016g ==> 16mg
hey can describe me in detail how find answer problem, have correct answer don't know how find it,
silver acetate , copper(11) sulfate react in double replacement reaction. if 15.0 mg of each reactant used, how of each product forms?
again
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