Can there be spectator ions in a double-replacement reaction?

if include state symbols products get:
ba(oh)2(aq) + h2so4(aq) → baso4(s) + h2o(l)

2 products not produce ions because baso4 precipitates insoluble solid , h2o non- dissociating liquid. ions reactants enter reaction , there no spectator ions.

contrast double displacement reaction produce spectator ions:

nacl(aq) + agno3(aq) → agcl(s) + nano3(aq)
if show full ionic equation get:
na+(aq) + cl-(aq) + ag+(aq) + no3-(aq) → agcl(s) + na+(aq) + no3-(aq)

see have na+(aq) ions , no3-(aq) ions on reactant side , unchanged on product side. means these ions have not entered reaction , remain unchanged. spectator ions - not take part - merely "look on"to reaction.

answer question: can there spectator ions in double-replacement reaction?
answer is: yes - in fact @ guess double displacement reaction without spectator ions exception. far majority of double displacement reactions have spectator ions.

for example: identify spectator ion in reaction. ba(oh)2(aq)+h2so4(aq)-->baso4+ h20.
know answer says there no spectator ions, wondering why.

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